(3x+2/2x-4)^-6

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Solution for (3x+2/2x-4)^-6 equation: 


D( x )

3*x+(2/2)*x-4 = 0

3*x+(2/2)*x-4 = 0

3*x+(2/2)*x-4 = 0

4*x-4 = 0 // + 4

4*x = 4 // : 4

x = 4/4

x = 1

x in (-oo:1) U (1:+oo)

(3*x+(2/2)*x-4)^-6 = 0

1/((4*x-4)^6) = 0

x belongs to the empty set

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